用于根据指定的分隔符将字符串拆分为子字符串行的 iTVF 在接收到空值时中断 (TSQL)

Question

I have an inline table-valued function, which splits strings into row of substrings based on a specified separator.

It is as follows:

ALTER FUNCTION [dbo].[SplitString]
    (@List NVARCHAR(MAX),
     @Delim VARCHAR(255))
RETURNS TABLE
AS
    RETURN 
        (SELECT [Value], idx = RANK() OVER (ORDER BY n) 
         FROM 
             (SELECT 
                  n = Number, 
                  [Value] = LTRIM(RTRIM(SUBSTRING(@List, [Number],
                  CHARINDEX(@Delim, @List + @Delim, [Number]) - [Number])))
              FROM 
                  (SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
                   FROM sys.all_objects) AS x
              WHERE Number <= LEN(@List)
                AND SUBSTRING(@Delim + @List, [Number], LEN(@Delim)) = @Delim) AS y
        );
GO

Usage:

SELECT value 
FROM dbo.SplitString('a|b|c', '|')  

returns:

value
a
b
c

But when sending an empty value as the first argument, it doesn't return anything.

For example:

SELECT value FROM dbo.SplitString('','|')     

This doesn't return anything.

What modification I need to do to the dbo.SplitString function, so that it returns an empty result set, when an empty string is passed in as first argument?

PS: I can't use the inbuilt STRING_SPLIT function because of compatibility issues.

Answer 1

DelimitedSplit8K_LEAD (above) will always return a row and will be faster.

That said, for learning purposes let's fix your function. If you replace a blank value with your delimiter you will get the results you are looking for. You just need to replace every instance of @list with ISNULL(NULLIF(@List,''),@Delim). Now you have:

ALTER FUNCTION [dbo].[SplitString]
    (@List NVARCHAR(MAX),
     @Delim VARCHAR(255))
RETURNS TABLE
AS
    RETURN 
        (SELECT [Value], idx = RANK() OVER (ORDER BY n) 
         FROM 
             (SELECT 
                  n = Number, 
                  [Value] =     LTRIM(RTRIM(SUBSTRING(ISNULL(NULLIF(@List,''),@Delim), [Number],
              CHARINDEX(@Delim, ISNULL(NULLIF(@List,''),@Delim) + @Delim, [Number]) - [Number])))
              FROM 
                  (SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
                   FROM sys.all_objects) AS x
              WHERE Number <= LEN(ISNULL(NULLIF(@List,''),@Delim))
                AND SUBSTRING(@Delim + ISNULL(NULLIF(@List,''),@Delim),         
[Number], LEN(@Delim)) = @Delim) AS y
        );

Now, when you execute: DECLARE @list VARCHAR(max) = '', @delim VARCHAR(255) = '|'

SELECT *
FROM dbo.SplitString(@list,@delim)

You get:

Value    idx
------   ------
         1

Answer 2

Thanks @Larnu and @Bernie for all suggestions.
After so much of research, I started iterating and getting expected result. I achieved this by simple while loop and, string functions of SQL.

CREATE FUNCTION [SplitString]
(
   @ActualString      VARCHAR(MAX),
   @DelimiterCharacter  VARCHAR(10)
)
RETURNS @TableRes TABLE (Id INT IDENTITY(1,1),Value VARCHAR(MAX))
AS
BEGIN
DECLARE @SubStr VARCHAR(MAX)
     WHILE (CHARINDEX(@DelimiterCharacter  ,@ActualString)<>0)
     BEGIN
         SET @SubStr=SUBSTRING(@ActualString,1,CHARINDEX(@DelimiterCharacter ,@ActualString)-1)
         SET @ActualString= STUFF(@ActualString,1,CHARINDEX(@DelimiterCharacter,@ActualString),'') 
         INSERT INTO @TableRes
         SELECT @SubStr

      END
       INSERT INTO @TableRes
       SELECT @ActualString


       RETURN
END

This will work for all cases
1)When Actual string is empty string like select * from [dbo].[SplitString]('',',')
2)When Actual string has empty string at end like select * from [dbo].[SplitString]('a,b,',',')