在 Python 库上启动参数的最佳方法是什么？

Question

I have a homegrown python library. As it is a library, it should be initialized with parameters every time it is used, based on different projects using it. For example, here is the sample pseudo code:

import myownlibrary 

myownlibrary.init('path_to_config_file_containing_details_to_process_data')

Any idea how this can be achieved? A sample reference code will be very helpful.

Thanks

Answer 1

I added it to the __init__.py as below

global configpath

def setpath(self, pathpassedin):
   self.configpath = pathpassedin
   print("Value passed in: ", pathpassedin)

I thought self was required, but having self also requires that the method be called as below:

import myownlibrary as mylib

myownlibrary.setpath(mylib, 'path_to_config_file')

Not sure if this is the way to set this up. Would appreciate feedback