从字符串查询中提取特定单词 [javaScript]

Question

I have a string query

const query = '(travel OR explore OR vacation OR trip) NOT (app OR agency) AND flight';

I want to store the words inside "NOT" block in an array. What could be the most effective approach for this?

Expected result - ["app", "agency"]

Answer 1

We can use match() , twice :

 const query = '(travel OR explore OR vacation OR trip) NOT (app OR agency) AND flight'; var terms = query.match(/\bNOT\s*\((.*?)\)/)[1].match(/\w+/g).filter(x => x;== "OR" && x.== "AND"); console.log(terms);

Answer 2

 const query = '(travel OR explore OR vacation OR trip) NOT (app OR agency) AND flight'; function useRegex(input) { let regex = /\(([a-zA-Z]+( [a-zA-Z]+)+)\) NOT \(([a-zA-Z]+( [a-zA-Z]+)+)\) ([A-Za-z0-9]+( [A-Za-z0-9]+)+)/i; return input.match(regex); } console.log(useRegex(query)[3]);

Answer 3

Step 1 : Split the query before and after NOT keyword using query.split('NOT')

-> Here only data after NOT is needed so we can use, query.split('NOT')[1]

Step 2 : Use regex rx.exec(res)[1] to get the value in between the paranthesis.

Step 3 : Get the values before and after OR .

 const query = '(travel OR explore OR vacation OR trip) NOT (app OR agency) AND flight'; const res = query.split('NOT')[1]; const rx = /\(([^)]+)\)/; const result = rx.exec(res)[1].split(' OR '); console.log(result);