通过单个 lambda function 将s3中托管的文件内容解压到多个cloudfront url

Question

Is there any specific way to unzip single file contents from s3 to multiple cloudfront urls by triggering lambda once.

Lets say in there is a zip file contains multiple jpg/ png files already uploaded to s3. Intention is to run lambda function only once to unzip all its file content and make them available in multiple cloudfront urls.

in s3 bucket

archive.zip
   a.jpg
   b.jpg
   c.jpg

through cloudfront

https://1232.cloudfront.net/a.jpg
https://1232.cloudfront.net/b.jpg
https://1232.cloudfront.net/c.jpg

I am looking for a solution such that lambda function trigger function calls whenever a s3 upload happens and make all files available in the zip through cloudfront multiple urls.

Answer 1

Hello Prathap Parameswar,

I think you can resolve your problem like this:

• First you need to exact your zip file
• Seconds you upload them again to S3.

This is lambda python function:

import json
import boto3
from io import BytesIO
import zipfile

def lambda_handler(event, context):
    # TODO implement
    
    s3_resource = boto3.resource('s3')
    source_bucket = 'upload-zip-folder'
    target_bucket = 'upload-extracted-folder'

    my_bucket = s3_resource.Bucket(source_bucket)

    for file in my_bucket.objects.all():
        if(str(file.key).endswith('.zip')):
            zip_obj = s3_resource.Object(bucket_name=source_bucket, key=file.key)
            buffer = BytesIO(zip_obj.get()["Body"].read())
            
            z = zipfile.ZipFile(buffer)
            for filename in z.namelist():
                file_info = z.getinfo(filename)
                try:
                    response = s3_resource.meta.client.upload_fileobj(
                        z.open(filename),
                        Bucket=target_bucket,
                        Key=f'{filename}'
                    )
                except Exception as e:
                    print(e)
        else:
            print(file.key+ ' is not a zip file.')

Hope this can help you