Javascript 只允许字母表、空格和 - 的正则表达式

Question

I want a regular expression that allow only alphabet, one space after word, and - only it will not accept two word but single space after word allowed. Any ther special character are not allowed. Example

John -> true
John(space) -> true
John-Doe -> true
John-Doe(space) -> true
(space)John -> false
John Doe -> false

I am trying using this [a-zA-Z-][a-zA-Z -] But not working exactly. Please help.

Answer 1

If you don't want to allow consecutive hyphens -- in the pattern, you might write the pattern as:

^[A-Z][a-z]+ ?(?:-[A-Z][a-z]+ ?)?$

Explanation

• ^ Start of string
• [AZ][az]+? Match a char AZ and 1+ chars az followed by an optional space (or [A-Za-z]+ if you want to allow mixed chars)
• (?:-[AZ][az]+?)? Optionally match the same as the preceding pattern with a leading -
• $ End of string

See a regex demo

---

If you want to allow all mixed chars with an optional space at the end:

^[A-Za-z-]+ ?$

Regex demo