Python Telethon - 定时发送消息

Question

I'm trying to send a message to my group at defined time intervals, but I get a warning in the output the first time I try to send the message. Next times no warning, but nothing is posted in the group. I'm the owner of the group so in theory there shouldn't be any permissions issues.

Code

from telethon import TelegramClient
import schedule

def sendImage():
    apiId = 1111111
    apiHash = "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
    phone = "+111111111111"
    client = TelegramClient(phone, apiId, apiHash)

    toChat = 1641242898

    client.start()

    print("Sending...")
    client.send_file(toChat, "./image.jpg", caption="Write text here")

    client.disconnect()
    return

def main():
    schedule.every(10).seconds.do(sendImage)

    while True:
        schedule.run_pending()

if __name__ == "__main__":
    main()

Output

Sending...
RuntimeWarning: coroutine 'UploadMethods.send_file' was never awaited
  client.send_file(toChat, "./image.jpg", caption="Write text here")
RuntimeWarning: Enable tracemalloc to get the object allocation traceback
Sending...
Sending...
Sending...

Answer 1

Telethon uses asyncio , but schedule wasn't designed with asyncio in mind. You should consider using an asyncio -based alternative to schedule , or just use Python's builtin functions in the asyncio module to "schedule" things:

import asyncio
from telethon import TelegramClient

def send_image():
    ...
    client = TelegramClient(phone, apiId, apiHash)

    await client.start()
    await client.send_file(toChat, "./image.jpg", caption="Write text here")
    await client.disconnect()

async def main():
    while True:  # forever
        await send_image()  # send image, then
        await asyncio.sleep(10)  # sleep 10 seconds

    # this is essentially "every 10 seconds call send_image"

if __name__ == "__main__":
    asyncio.run(main())

You should also consider creating and start() ing the client inside main to avoid recreating it every time.

Answer 2

This means that you do not give time for the operation to be done, try these changes:

from telethon import TelegramClient
import schedule

async def sendImage(): # <- make it async
    apiId = 1111111
    apiHash = "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
    phone = "+111111111111"
    client = TelegramClient(phone, apiId, apiHash)

    toChat = 1641242898

    client.start()

    print("Sending...")
    await client.send_file(toChat, "./image.jpg", caption="Write text here") # <- here too add await

    client.disconnect()
    return

def main():
    schedule.every(10).seconds.do(client.loop.run_until_complete(sendImage))

    while True:
        schedule.run_pending()

if __name__ == "__main__":
    main()

other thing i don't think that you should keep connecting and disconnecting, in my opinion client.start() should be out of this function and client.disconnect too

Answer 3

As the output says you need to await the response of the coroutine. The code may trigger exceptions which should be handled.

try:
    client = TelegramClient(...)
    client.start()
except Exception as e:
    print(f"Exception while starting the client - {e}")
else:
    try:
        ret_value = await client.send_file(...)
    except Exception as e:
        print(f"Exception while sending the message - {e}")
    else:
        print(f"Message sent. Return Value {ret_value}")