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将 curl 命令翻译成 python requests.get

[英]Translate curl command to python requests.get

I have the following curl command which I can use to retrieve a list of users from a specific group in PagerDuty:我有以下 curl 命令,可用于从 PagerDuty 中的特定组检索用户列表:

curl -H "Accept: application/vnd.pagerduty+json;version=2" -H "Authorization: Token token=xxx" -X GET --data-urlencode "team_ids[]=abc" 'https://api.pagerduty.com/users'

How can I translate this exact command to run in a python get.requests() command?我如何翻译这个确切的命令以在 python get.requests() 命令中运行? I can't seem to get it to work.我似乎无法让它工作。 This is what I'm currently trying but it doesn't filter on the group:这是我目前正在尝试的,但它不会过滤组:

response = requests.get(
        'https://api.pagerduty.com/users', params = {"data-urlencode": "team_ids[]=abc"}, headers={'Accept': 'application/vnd.pagerduty+json;version=2','Authorization': 'Token token=xxx'}
    )

    )

Thanks!谢谢!

Simply omit --data-urlencode from your params:只需从您的参数中省略--data-urlencode

import requests

params = {
    'team_ids[]':"abc",
    "offset": '0',
}
headers = {
    'Accept': 'application/vnd.pagerduty+json;version=2',
    'Authorization': 'Token token=xxx',
}

response = requests.get('https://api.pagerduty.com/users', params=params, headers=headers)

if first solution is hard for you u can use one of websites that convert curl command to pytho/php etc... code如果第一个解决方案对你来说很难,你可以使用一个将 curl 命令转换为 pytho/php 等的网站...代码

curlconverter.com curlconverter.com

https://sqqihao.github.io/trillworks.html https://sqqihao.github.io/trillworks.html

https://www.scrapingbee.com/curl-converter/python/ https://www.scrapingbee.com/curl-converter/python/

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