[英]Round decimals of numbers in Python
I have a list, each row contains 4 floats (should represent a bounding box)我有一个列表,每行包含 4 个浮点数(应该代表一个边界框)
[[7.426758, 47.398349, 7.850835593464796, 47.68617800490421],
[7.850835593464796, 47.398349, 8.274913186929592, 47.68617800490421],
[8.274913186929592, 47.398349, 8.698990780394388, 47.68617800490421]]
I would like to round each float to 6 decimal places.我想将每个浮点数四舍五入到小数点后 6 位。 I tried to round the numbers using pandas, but it also didn't work.
我尝试使用 pandas 对数字进行四舍五入,但它也没有用。
{49: '7.850835593464796,49.12532302942521,8.274913186929592,49.413152034329414',
17: '7.850835593464796,47.9740070098084,8.274913186929592,48.26183601471261',
71: '10.395301154253572,49.70098103923361,10.819378747718368,49.988810044137814'}
Try numpy.around
:尝试
numpy.around
:
# lst is your list
np.around(lst, 6).tolist()
Output: Output:
[[7.426758, 47.398349, 7.850836, 47.686178],
[7.850836, 47.398349, 8.274913, 47.686178],
[8.274913, 47.398349, 8.698991, 47.686178]]
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