python编码错误如何解决？

Question

Topic: Check adjacent odd numbers
Problem description: Enter 5 numbers

Input description: Whether the output has adjacent odd numbers.

Output description: If there are adjacent odd numbers, output the first group of adjacent odd numbers, otherwise, turn out NO.

 Sample Input: Sample Output: 5 6 7 8 9 NO⏎ 8 9 11 13 15 9,11⏎

Writing condition:
Input: Use the list(), map(), int() functions to convert the input string to a sequence of integers

Process: Use a loop to check for adjacent odd numbers

Output: apply f-string

num1, num2, num3, num4, num5 = map(int,input().split())
list1= [num1, num2, num3, num4, num5]
for i in range(list1[0], list1[4]):
  if i%2 != 0:
    for j in range(list1[1], list1[4]):
      if j%2 != 0 :
        break
    print(f'{i, j}')
  else :
    print('NO')

I used for-loop to write the code but the result is a wrong error. I excepted that when I input 5 6 7 8 9 and the actual result is NO . However, my wrong result is

(5, 7)
NO 
(7, 7)
NO

Answer 1

When you use range you are creating an entirely new set of numbers. You need to use the list directly. An easy way to solve this problem is by using zip on the list and an offset of the list

This way you can compare the current number with the next number without creating more loops.

#you can apply your split results directly to the list
#no need to unpack and repack the data
data = list(map(int,input().split()))

for i,j in zip(data, data[1:]):

    #you don't need explicit equality (ie. i%2!=0)
    #both of these either "are" or "aren't"
    if i%2 and j%2:
        #the way you wrote your fstring 
        #you were actually printing a tuple
        print(f'{i}, {j}')
        break
else: 
    #if `break` was never reached
    print('NO')