将道具推入 Supabase 过滤 - VUE3，Supabase

Question

Trying to push through a prop to the.like filtering option in supabase function. Due to.like needing % in value, im not sure how to push the prop through. Please see below.

const fetchData = async () => {
 const { data, error } = await supabase
 .from('sneaker')
 .select()
 .eq('brand', props.model?.brand)
 .like('name', '%Yeezy%')
 filteredList1.value = data
 console.log(data)
}

I would like to have props.model?.name instead of '%Yeezy%'. I have tried adding in the prop like stated but does not work. Much appreciated.

Answer 1

Have you tried concatenating the string?

.like('name', `%${props.model?.name}%`)