读取文本或 CSV 文件并分成以空格分隔的组

Question

I have a .csv file with data as:

20
40
25

50
60
80

10
25
34
75
50

50
60

I need to read this file and create groups of numbers whenever a blank value is found. Hence, for the example above, it should become:

final_list = [
    [20, 40, 25],
    [50, 60, 80],
    [10, 25, 34, 75, 50],
    [50, 60]
]

Answer 1

Just read a csv file line by by line & than one blank string in the list, you can use itertools.groupby like this:

from itertools import groupby
with open(r"codeMaster.csv") as fp:
    line = fp.readlines()

line = [i.strip() for i in line]

print([list(g) for k, g in groupby(line, key=bool) if k])

Gives #

[['20', '40', '25'], ['50', '60', '80'], ['10', '25', '34', '75', '50'], ['50', '60']]

More pythonic ##

with open(r"CodeMaster.csv") as fp:
    line = fp.readlines()

line = [i.strip() for i in line]
result = [[]]
for i in line:
    if not i:
        result.append([])
    else:
        result[-1].append(i)
print(result)

Also Gives #

[['20', '40', '25'], ['50', '60', '80'], ['10', '25', '34', '75', '50'], ['50', '60']]