如何将这两个列表交织成一个列表？

Question

a = ['a', 'b', 'c']
b = [10, 20, 30]

output should be like [[a:10], [b:20], [c:30]]

I do know how to use the zip to interweave two lists

l = []
for x,y in zip(a,b):
    l.append([x,y])

And the output is: [['a', 10], ['b', 20], ['c', 30]] instead of [[a:10], [b:20], [c:30]]

How should I make like this with ':' Thanks

Answer 1

Assuming that you mean to create a list of singleton dicts, you can zip the two lists, convert sequence of value pairs to singletons with another zip , and map the resulting sequence to the dict constructor:

list(map(dict, zip(zip(a, b))))

Or use a list comprehension:

[{i: j} for i, j in zip(a, b)]

Both return:

[{'a': 10}, {'b': 20}, {'c': 30}]