[英]C - repeat a string for a specific number of times in anothervariable
I want to repeat a string - for example hello - for a specific number of imes - for example 3 times -, but it doesnt work:) The example should look like this: hellohellohello, but I get no output or i get HHHHHHHHHHH...我想重复一个字符串 - 例如你好 - 对于特定数量的 imes - 例如 3 次 - 但它不起作用:) 该示例应如下所示:hellohellohello,但我没有得到 output 或者我得到 HHHHHHHHHHH.. .
here is my code:这是我的代码:
char *repeat_str(size_t count, char *src) {
int length = strlen(src);
int z = length;
char *ausgabe = calloc((length*(count+1)), sizeof(char));
for(int i = 0; i<=((int) count);i++){
for(int j =0; j< length; j++){
ausgabe[i+j+z] = src[j];
}
z=z*2;
}
//printf("%s\n", ausgabe);
return(ausgabe);
}
If i remove the 'z' in the brackets of 'ausgabe', i get the output HHHHHHHH%, with the z I just get no output. Could bdy pls help me change this behavoiur - and more important, understant why it does that?如果我删除 'ausgabe' 括号中的 'z',我得到 output HHHHHHHH%,而 z 我只是没有 output。bdy 可以帮我改变这个行为 - 更重要的是,了解它为什么这样做?
The strcat
function is your friend. strcat
function 是你的朋友。 We can calloc
a buffer long enough for n
source strings, plus one for the null terminator, and then just concatenate the source string onto that buffer n
times.我们可以为
n
源字符串调用一个足够长的缓冲区,再加上一个用于calloc
终止符的缓冲区,然后将源字符串连接到该缓冲区n
次。
char *repeat_string(int n, const char *s) {
int len = strlen(s) * n + 1;
char *result = calloc(len, 1);
if (!result) return NULL;
for (int i = 0; i < n; i++) {
strcat(result, s);
}
return result;
}
As you are always referring *src
, which is fixed to the first letter of src
, the result looks like repeating it.由于您总是引用
*src
,它固定为src
的第一个字母,结果看起来像是在重复它。 Would you please try instead:你能试试吗:
char *repeat_str(size_t count, char *src) {
int length = strlen(src);
char *ausgabe = calloc(length * count + 1, sizeof(char));
for (int i = 0; i < count; i++) {
for (int j = 0; j < length; j++) {
ausgabe[i * length + j] = src[j];
}
}
//printf("%s\n", ausgabe);
return ausgabe;
}
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