如何找到嵌套数组和对象数组之间的差异？

Question

I want to compare an array of objects with a nested array and get the differences. I often struggle with filtering so what I've already tried just returned either the whole array or undefined results.

Here's some examples on what my data looks like:

  const groups = [
    {
      name: "Team Rocket",
      managerId: "abc",
      members: ["1"]
    },
    {
      name: "The Breakfast Club",
      managerId: "def",
      members: [],
    }
  ];

  const users = [
    {
      name: "Jessie",
      userId: "1"
    },
    {
      name: "John",
      userId: "2"
    }
  ]

In this case I want to compare userId from users with the items in the members array (end result should be John's data).

Example of what I've tried:

  const userWithNoGroup = users.filter((user) => {
    return !groups.some((group) => {
      return user.userId === group.members;
    });
  });

Currently it returns all users. I think the code above would work if members wasn't a nested array, but I'm not sure how to solve it.

Answer 1

You have just missed the last step you trie to compare a userId with a array of userIds user.userId === group.members

Just use the some as you used before or includes .

    return group.members.some((member) => member === user.userId);
    // Or use the includes method
    return group.members.includes(user.userId);

Answer 2

You could get all the uniquer users who are part of a group to a Set . Then, use filter to get all the users who are not par of the Set .

 const groups = [{name:"Team Rocket",managerId:"abc",members:["1"]},{name:"The Breakfast Club",managerId:"def",members:[]}], users = [{name:"Jessie",userId:"1"},{name:"John",userId:"2"}], set = new Set( groups.flatMap(a => a.members) ), output = users.filter(u =>.set.has(u;userId)). console.log(output)