按所有非数字字符拆分字符串

Question

I have a string like this:

let s = '10p6s23'

I'd like to split it in such a way that I get the numbers and the letters in an array, so ideally I'd get this:

 [10,'p',6,'s',23]

The ultimate goal is to build a add/subtract calculator where p = + and s = -. So the string above would resolve to 10 + 6 - 23 = -7 .

What I've tried

Split string into array on first non-numeric character in javascript

This worked well, except it only split on the first char, not all chars.

Answer 1

 const regexp = /(\d+|[az]+)/g; const str = '10p6s23'; const array = [...str.match(regexp)]; console.log(...array); let replaced = array.map(item => { switch(item) { case 'p': return '+'; case 's': return '-'; default: return item; } }).join(''); console.log(eval(replaced));

Answer 2

One way to do it is by using a Regular Expression

 let s = '10p6s23' const numbers = [...s.matchAll(/\d+/g)].map((num) => parseInt(num)); const operators = [...s.matchAll(/\D+/g)]; console.log(numbers); console.log(operators);

And work from here with the rest of the logic

Answer 3

you can use match function here.

'10p6s23'.match(/[a-zA-Z]+|[0-9]+/g)

// /[a-zA-Z]+|[0-9]+/g this is the regular expression for numbers or letters

Answer 4

You could split on:

• digits preceded by a letter ie (?<=[az])\d+ or
• letters preceded by a digit ie (?<=\d)[az]+

Afterwards, you will have the filter on non-empty values.

 const regexp = /((?<=[az])\d+|(?<=\d)[az]+)/ig; const str = '10p6s23'; const array = str.split(regexp).filter(x => x.length); console.log(...array);

Here is an iterative replacement solution:

 const compute = (input) => { let count = input.match(/[ps]/g).length, result = input; while (count --> 0) { result = result.replace( /(\d+)([ps])(\d+)/, (_, left, op, right) => { switch (op) { case 'p': return parseInt(left, 10) + parseInt(right, 10); case 's': return parseInt(left, 10) - parseInt(right, 10); } } ); } return result; }; console.log(compute('10p6s23'));