[英]Pad a bitstring with 0's to form full bytes
I have bitstring such as '01110'.我有诸如“01110”之类的位串。 I want to return numbers of right-padded 0s so that it forms full bytes (number of bits divisible by 8).
我想返回右填充 0 的数量,以便它是 forms 个完整字节(可被 8 整除的位数)。
What I tried so far:到目前为止我尝试了什么:
padding_len = len(bitstr) % 8
bitstr += '0' * padding_len
padding_len = (8 - len(bitstr)) % 8
bitstr += '0' * padding_len
Alternatively,或者,
import math
target_len = math.ceil(len(bitstr) / 8) * 8
bitstr = bitstr.ljust(target_len, '0')
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