加载 json 数据并在没有 swagger-ui 的情况下创建文档

Question

I have seen the following link for my query, Python Flask automatically generated Swagger/OpenAPI 3.0 but i want to load json file inside apispec.

Following is my tried code:

import json

with open("rest_api_swagger.json", 'r') as x:
    a = json.loads(x.read())

final_data = []

def solve(x):
    if type(x) == dict:
        #print(x)
        for k,v in x.items():
            if type(v) == dict:
                print("dict data entered: ","key name: ",k,"---->>",v)
                
                solve(v)
                
            elif type(v) == list:
                for q in v:
                    print("array data entered: ","key name: ",k,"---->>",q)

            elif type(v) == str:
                if 
                print("This is string: ","key name: ",k,"---->>",v) 

solve(a)

spec = APISpec(
    "finaldata array here"
    )

I know array data cannot be given into APISpec but just giving an example, is there a way to load json data into APISpec directly?

I know APISpec generates json data but what i want is the api documetation, without using swagger-ui. Is there a way to create swagger documentation with json objects after loading swagger.json?

Answer 1

can try to use flask-toolkits this one link

upon implemented you can access both in your browser

• openapi (http://localhost:xxxx/docs)
• swagger/openapi json (http://localhost:xxxx/openapi.json)