如何在 azure yaml 管道任务中的 workingDirectory 中使用 glob 模式？

Question

In one of the task in onebranch Azure pipelines, I am installing one package say abc. After installation the folder gets created named abc.some_version (like abc.1.0.1). But the installation of the package installs the latest package. So the folder name may get changed. In next task I want to go to the folder inside above installed package /packages/abc.1.0.1/build to execute some command abc.exe do_something .

    - script: |
        nuget install abc
      displayName: Install abc
      workingDirectory: $(Build.SourcesDirectory)\src

    - script: |
        abc.exe do_something -o "$(Build.SourcesDirectory)\src"
      displayName: Create
      workingDirectory: $(Build.SourcesDirectory)\src\packages\abc.1.0.1\build

I want to use glob pattern in workingDirectory parameter of script like $(Build.SourcesDirectory\src\packages\abc.*\build

So for future if any new package version comes, I dont have to change the yaml file again. After using the '*' in the workingDirectory path, I found that azure pipeline is taking * as a part of path itself.

Is there any way I can match the pattern inside workingDirectory or is there any other way to do this?

Answer 1

Glob pattern is not supported when defining in

workingDirectory: $(Build.SourcesDirectory)\src\packages\abc.1.0.1\build

You must hard code in the above scenario.

Glob pattern will work well in command line task Try command line to "cd" to the path.

cd C:\test\*\1