警告：指针与 integer 比较

Question

I started learning C language and my task is to write a script that will check the text in the txt file for the presence of the word ananas, but you can't use strlen(), strcpy(), strcmp() . I wrote code that doesn't work, but the output is simple 0. I understand why it outputs something, but I don't understand how to do it so it worked fine. And when I compile the code, I get this error

warning: comparison between pointer and integer
if(c[i] == s || ss){

This is my code

#include <stdio.h>
#include <stdlib.h>


int main() {
  FILE *f;
  char c[1000];
  char a[] = {'a'};
  char aa[] = {'A'};

  char n[] = {'n'};
  char nn[] = {'N'};

  char s[] = {'s'};
  char ss[] = {'S'};
  int g = 0;
  int col = 0;

  
  f = fopen("bananas1.txt", "r");
  fgets(c, 1000, f);
  for(int i = 0; i < 1000; i++){
    for(int q = 0; q < 1;){
      if(c[i] == a || aa){
        q++;
      }
      if(c[i] == n || nn){
        q++;
      }
      if(c[i] == s || ss){
        q++;
      }
      if(q == 1){
        g++;
        q = 0;
      }
      if(q == 0){
        g = 0;
      }

    }
    if(g == 6){
      col++;
    }

  }
  printf("%d", col);
  fclose(f);

  return 0;
}

Here is the text that I need to check in the bananas1.txt file

Bananas are edible fruits, botanically berries. In some countries, bAnAnAs used for cooking are called plantains, distinguishing them from dessert bananaS. The fruits grow in clusters hanging from the top of the plant. Almost all modern edible seedless BANANAS come from two wild species of Musa acuminata and Musa balbisiana. The scientific names of most cultivated bananas are Musa acuminata, Musa balbisiana, and Musa X paradisiaca, depending on their genomic constitution.

As you can see, there is the word bananas, and it contains the word bananas; I need to count the number of ananas words in this text.

Answer 1

I assume that this

 if(c[i] == a || aa){

is meaning to say

"if c[i] is either 'a' or 'aa' then..."

Sadly, C doesn't work like that. The attempt to compare a char (c[i) with an array of chars (a, even though it's only one character) is why you are getting the error.

You need

  if(c[i] == 'a')....

or

 char a = 'a';
 if(c[i] == a)...

there is no way to look to see if one char is equal to 2 chars (.). If you need to look for 'aa' then you have to look for an a then look at the next char too

Also you cannot do shortcut 'ors'

  if(c[i] == 'a' || 'b')

does not say "if c[i] == a or c[i] == b".