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为什么我们不需要在这个问题中减去字节偏移位?

[英]Why don't we need to subtract byte offset bits in this problem?

In the following question: How to find tag bit in cache given word address在以下问题中: How to find tag bit in cache given word address

They have found the number of tag bits by 32 - number of index bits - word offset .他们通过32 - number of index bits - word offset But in the book, they also mentioned the following:但在书中,他们还提到了以下内容:

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Why are we not subtracting 2 here in the problem?为什么我们不在问题中减去 2?

For anyone who is getting confused like me, it is as follows as far as I know.对于任何像我一样感到困惑的人,据我所知如下。

Given word address 3 , we can convert it to by address which is one of address between 12 and 15 inclusive because word is 4 bytes and thus you have to multiply word address by 4.给定字地址3 ,我们可以将其转换为 by 地址,该地址是1215之间的地址之一,因为字是 4 个字节,因此您必须将字地址乘以 4。

If you convert 12 and 15 to binary it will be ...001100 and ...001111 and you have to get least 2 significant bits for byte offset and the next 1 bit for word( block) offset which leaves 001 in both cases.如果将1215转换为二进制,它将是...001100 001100 和...001111并且您必须为字节偏移获得至少2有效位,并为字(块)偏移获得下一个1位,这在两种情况下都为001

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