C#：如何从类型变量中获取实际类型

Question

Given the Type type parameter, How can I create the dictionary: Dictionary<Type, DataCollection<T>> , where where typeof(T) == type ?

I tried Dictionary<Type, DataCollection<Type>> , but it doesn't work because DataCollection<T> accepts data of type T (where typeof(T) == type ), not of type Type .

Also, I cannot make it generic: Dictionary<T, DataCollection<T>> because I want all types to be accepted, not just a single type T

Answer 1

You can always create the type with this:

Type type = typeof(int);
Type typeDC = typeof(DataCollection<>);

var t = typeof(Dictionary<,>);
var x = t.MakeGenericType(type, typeDC.MakeGenericType(type));

object o = Activator.CreateInstance(x);

You would then need to use reflection to call the methods of o or to pass o to a strongly-typed method.