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PostgreSQL 中字符串数组中空值的计数

[英]Count of empty values in string array in PostgreSQL

I want to check Projects column values have the same values for all the same values of PartNo and PartName columns.我想检查 Projects 列值对于 PartNo 和 PartName 列的所有相同值是否具有相同的值。 Projects column data type is character variyng[].项目列数据类型是字符 variyng[]。 For example:例如:

PartNo型号 PartName零件名称 Projects项目
1 1个 3 3个 6;5 6;5
1 1个 3 3个
1 1个 3 3个
3 3个 2 2个 5;5 5;5

In this case, Projects have different values (6;5) and () for the same PartName(3) and PartNo(1).在这种情况下,对于相同的 PartName(3) 和 PartNo(1),Projects 具有不同的值 (6;5) 和 ()。

This is my query, but it does not work with empty character variyng[] in projects column!这是我的查询,但它不适用于项目列中的空字符 variyng[]!

          SELECT COUNT(*) from (
      select c.partno, c.partname
   FROM unnest(items) as c
   GROUP BY c.partno, c.partname
HAVING COUNT(distinct c.projects) > 1) as xxx
   INTO errCount;

   IF errCount > 0 THEN
      RETURN QUERY 
         SELECT 0 as status, format('Projects value should be the same for all Codes of the Part No %s and Name %s',c.partno,c.partname) as message  
         FROM unnest(items) as c
   GROUP BY c.partno, c.partname
HAVING COUNT(distinct c.projects) > 1 
         ;
      RETURN;
   END IF;

In the case of two different values in projects (not empty array), it works.在项目中有两个不同值(不是空数组)的情况下,它有效。

you can use a query like this with您可以使用这样的查询

coalesce合并

function to convert null in array[null]将数组[null]中的null转换为null的函数

WITH tt AS (
    SELECT
        partno,
        partname,
        COALESCE ( project, ARRAY [null] ) AS pro 
    FROM
        tab1 
    ) SELECT
    *,
    COUNT ( pro ) AS num 
FROM
    tt 
GROUP BY
    partno,
    partname,
    pro

to create test table:创建测试表:

CREATE TABLE "tab1" (
  "pk" serial4 primary key,
  "partno" int4,
  "partname" int4,
  "project" varchar[] 
);


INSERT INTO "tab1" (partno,partname,project) VALUES ( 1, 3, '{6,5}');
INSERT INTO "tab1" (partno,partname,project) VALUES ( 1, 3, NULL);
INSERT INTO "tab1" (partno,partname,project) VALUES ( 1, 3, NULL);
INSERT INTO "tab1" (partno,partname,project) VALUES ( 3, 2, '{5,5}');

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