在 MySQL 中使用非空条件 LAG() 函数

Question

I tried applying a couple solutions from here , but my question seems to be somewhat different from the OP's from this post.

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I have a large dataset data in MySQL:

id          date          val
aaaaa       2021-01-01    TRUE
aaaaa       2021-01-02    FALSE
aaaaa       2021-01-03    FALSE
aaaaa       2021-01-04    TRUE
aaaaa       2021-01-05    FALSE
aaaaa       2021-01-06    TRUE
aaaaa       2021-01-07    FALSE
...
aaaaa       2021-12-31    FALSE
aaaab       2021-01-01    TRUE
aaaab       2021-01-02    FALSE
...
zzzzz       2021-12-31    FALSE

Here, id is a string-type data, date ranges from 2021-01-01 to 2021-12-31 without any missing days, and val contains a boolean value, TRUE or FALSE . data is ordered by id, date .

I would like to add two columns, lagged_date and date_diff .

• lagged_date contains the previous date of the id where val = TRUE .
• date_diff calculates the difference of the number of days between date and lagged_date in that row.

Ideally, my final dataset should look like this:

id          date          val        lagged_date     date_diff
aaaaa       2021-01-01    TRUE       NULL            NULL
aaaaa       2021-01-02    FALSE      2021-01-01      1
aaaaa       2021-01-03    FALSE      2021-01-01      2
aaaaa       2021-01-04    TRUE       2021-01-01      3
aaaaa       2021-01-05    FALSE      2021-01-04      1
aaaaa       2021-01-06    TRUE       2021-01-04      2
aaaaa       2021-01-07    FALSE      2021-01-06      1
...
aaaaa       2021-12-31    FALSE      2021-12-25      6
aaaab       2021-01-01    TRUE       NULL            NULL
aaaab       2021-01-02    FALSE      2021-01-01      1
...

(Note that this data is also ordered by id, date )

I tried a following query:

SELECT *,
       MAX(val) OVER (
          PARTITION BY id, val
          ORDER BY date
          ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING
       ) AS lagged_date,
       DATE_DIFF(date, lagged_date, DAY) AS date_diff
  FROM data

but the lagged_date does not produce my desired output, only produces the lagged val . I tried MAX(date) also, but to no avail.

Any insight is appreciated.

Answer 1

Use subquery to find the previous date for each 'id' where is 'TRUE' then use DATE_DIFF function.

SELECT t1.id, t1.date, t1.val,
  (SELECT t2.date FROM data t2 WHERE t2.id = t1.id AND t2.val = TRUE AND t2.date < t1.date ORDER BY t2.date DESC LIMIT 1) as lagged_date,
  DATEDIFF(t1.date, (SELECT t2.date FROM data t2 WHERE t2.id = t1.id AND t2.val = TRUE AND t2.date < t1.date ORDER BY t2.date DESC LIMIT 1)) as date_diff
FROM data t1