如何逐行保存文本文件（使用python或其他编辑器）

Question

I have a text file with 600 lines(\n), and I want to make 600 text files saving each line. So I want to write text files line by line, but I don't know how I can make it.

eg If I have 'all.txt' file with 600 lines, like: line1 aaaaaa line2 bbbbbb line3 cccccc... line 600 zzzzzz

-> I want to make results like this: 1.txt (content: aaaaaa) 2.txt (content: bbbbbb) 3.txt (content: cccccc)... 600.txt (content: zzzzzz)

I have python and notepad++, so it would be really nice to make these results using them. Thank you so much:)

This is what I tried, but the result was just 'i.txt' file with the last 600th line saved.

with open('all.txt',encoding='utf-8') as f:
    content = f.readlines()

len(content)
600

for i, line in enumerate(content):
    with open('i.txt', 'w') as f:
        f.write(content[i])

Answer 1

with open('all.txt') as f:
    for i, line in enumerate(f, 1):
        with open(f'{i}.txt', 'w') as f2:
            f2.write(line)