Pandas 滚动意味着偏移（不连续可用）日期

Question

given the following example table

Index	Date	Weekday	Value
1	05/12/2022	2	10
2	06/12/2022	3	20
3	07/12/2022	4	40
4	09/12/2022	6	10
5	10/12/2022	7	60
6	11/12/2022	1	30
7	12/12/2022	2	40
8	13/12/2022	3	50
9	14/12/2022	4	60
10	16/12/2022	6	20
11	17/12/2022	7	50
12	18/12/2022	1	10
13	20/12/2022	3	20
14	21/12/2022	4	10
15	22/12/2022	5	40

I want to calculate a rolling average of the last three observations (at least) a week ago. I cannot use.shift as some dates are randomly missing, and.shift would therefore not produce a reliable output.

Desired output example for last three rows in the example dataset:

Index 13: Avg of indices 8, 7, 6 = (30+40+50) / 3 = 40

Index 14: Avg of indices 9, 8, 7 = (40+50+60) / 3 = 50

Index 15: Avg of indices 9, 8, 7 = (40+50+60) / 3 = 50

What would be a working solution for this? Thanks!

Thanks!

Answer 1

I apologize for this ugly code. But it seems to work:

df = df.set_index("Index")
df['Date'] = df['Date'].astype("datetime64")
for id in df.index:
    dfs = df.loc[:id]
    mean = dfs["Value"][dfs['Date'] <= dfs.iloc[-1]['Date'] - pd.Timedelta(1, "W")].tail(3).mean()
    print(id, mean)

Result:

1 nan
2 10.0
3 15.0
4 23.333333333333332
5 23.333333333333332
6 36.666666666666664
7 33.333333333333336
8 33.333333333333336
9 33.333333333333336
10 33.333333333333336
11 33.333333333333336
12 33.333333333333336
13 40.0
14 50.0
15 50.0

Answer 2

MOSTLY inspired from @Aidis you could, make his solution an apply:

df['mean']=df.apply(lambda y:  df["Value"][df['Date'] <= y['Date'] - pd.Timedelta(1, "W")].tail(3).mean(), axis=1)

or spliting the data at each call which may run faster if you have lots of data (to be tested):

df['mean']=df.apply(lambda y:  df.loc[:y.name, "Value"][ df.loc[:y.name,'Date'] <= y['Date'] - pd.Timedelta(1, "W")].tail(3).mean(), axis=1)

which returns:

    Index       Date  Weekday  Value       mean
0       1 2022-12-05        2     10        NaN
1       2 2022-12-06        3     20        NaN
2       3 2022-12-07        4     40        NaN
3       4 2022-12-09        6     10        NaN
4       5 2022-12-10        7     60        NaN
5       6 2022-12-11        1     30        NaN
6       7 2022-12-12        2     40  10.000000
7       8 2022-12-13        3     50  15.000000
8       9 2022-12-14        4     60  23.333333
9      10 2022-12-16        6     20  23.333333
10     11 2022-12-17        7     50  36.666667
11     12 2022-12-18        1     10  33.333333
12     13 2022-12-20        3     20  40.000000
13     14 2022-12-21        4     10  50.000000
14     15 2022-12-22        5     40  50.000000

Answer 3

hello i hope that help you,

a=df.groupby("Weekday")['Value'].mean() # calculate mean for evry week
last3=df.iloc[-3:]#get last three rows in  dataset
mean=pd.DataFrame()
mean['mean']=a
result=last3.merge(mean, left_on='Weekday', right_on='Weekday')#megre the tow result on one dataframe