python 中正常运行时间命令的正则表达式

Question

"uptime" command has many different outputs. I'm trying to build regex pattern to match days and minutes. Need some help on this. Different outputs of uptime:

            15:22:04 up 45 days,  2:34,  2 users,  load average: 0.94, 1.17, 1.37
            15:30:12 up 21 min,  2 users,  load average: 1.56, 1.18, 1.18
            15:30:39 up 15:30,  1 user,  load average: 0.27, 0.40, 0.48

I tried the following but it works only for one of the output:

import re;
uptime_parser = re.compile('up\s+(\d+\s+\w+,\s+\d+:\d+)')

Expected output for each case:

1. up 45 days, 2:34
2. up 21 min
3. up 15:30

Answer 1

To match the different variations:

\bup\s+(?:(?:\d+\s+days,)?\s*\d{1,2}:\d{1,2}|\d+\s+min)\b

Explanation

• \bup\s+ Match the word up and 1+ whitespace chars
• (?: Non capture group for the alternatives
  • (?:\d+\s+days,)? Optionally match 1+ digits, 1+ whitespace chars and days,
  • \s*\d{1,2}:\d{1,2} Match optional whitespace chars and 1-2 digits : 1-2 digits
  • | Or
  • \d+\s+min Match 1+ digits, 1+ whitespace chars and min
• ) Close the non capture group
• \b A word boundary to prevent a partial word match

See a regex demo .