cuDeviceGetGraphMemAttribute() 的结果应该指向什么类型？

Question

cuDeviceGetGraphMemAttribute() takes a void pointer to a result variable. But - what type does it expect the pointed-to value to be? The documentation (for CUDA v12.0) doesn't say . I'm guessing it's an unsigned 64-bit type, but I want to make sure.

Answer 1

For all current attributes you can get with this function, the void * must point to a cuuint64_t .

_{Thanks goes to @AbatorAbeter for pointing out where this is stated.}