Apache Camel with Spring Boot - Zip 进程

Question

I am trying to process a zip file with Apache Camel. After making a call, I get a zip file and try to prepare the next call with this zip file as body. The call requires a form data with one name and zip file as value. I handle in this way:

process(e ->{
                    Object zip = e.getIn().getBody();                        
                    MultiValueMap<String, Object> body = new LinkedMultiValueMap<>();
                    body.add("file",zip);
                    e.getIn().setBody(body);
                })

But I receive the exception:

org.apache.camel.NoTypeConversionAvailableException: No type converter available to convert from type: org.springframework.util.LinkedMultiValueMap to the required type: java.io.InputStream with value {file=[[B@2b02c691]}

Any Ideas?

Cheers!

I tried to get the response in byte[] but it still dose not work.

Answer 1

As Jeremy said, the error says Camel is expecting (further in the process) a body of type InputStream , whilst you are obviously preparing a body of type MultiValueMap (BTW: why use a map if you have a single object to handle??)

I do not know what is the concrete type of your 'zip' object, but (if needed) you may have to replace current body with its inputstream equivalent:

process(e ->{
   // Print concrete type
   Object zip = e.getMessage().getBody(); 
   System.out.println("Type is " + zip.getClass() );
   // Convert body
   InputStream is = e.getMessage().getBody(InputStream.class); 
   // Replace body                       
   e.getMessage().setBody(is);
})