Bash：有什么方法可以在单引号括起的字符串中打印变量？

Question

I have a variable $NEWFILE which i want to print inside of a string surrounded by single quotes like this

cp '/path/to/file/$NEWFILE' /path/to/another/file

$NEWFILE can be variable like sunny fields.jpg . Basically I want the final output to be

cp '/path/to/file/sunny fields.jpg' /path/to/another/file

How do I go about this? I tried to put the whole string inside double quotes

cp "'/path/to/file/$NEWFILE'" /path/to/another/file

for $NEWFILE = 'sunny fields.jpg'. But it didn't work as expected

Answer 1

single quotes don't allow, by default, expand variables (feature that you need), so if you just replace it's supposed to works (it worked in my test):

cp "/path/to/file/$NEWFILE" /path/to/another/file

I just removed your single quotes.