Spring 引导：如何从 application.yml 中读取特定属性并忽略其他属性

Question

My goal is to read some property from application.yml file and ignore other properties. This is need for testing purposes - I want to read part of config and validate it. I want to ignore other properties because Spring Boot tring to handle it but this is no need for my test. Example.

Config:

first:
 property:
  {cipher}value    #for example Spring trying to handle cipher and throws exception

second:
 property:
  value

Class ( using String for simplification ):

@Configuration
public class Configuration {

  @Bean
  @ConfigurationProperties(prefix = "second.property")
  public String secondProperty() {
      return new String();
  }
}

Test class:

@SpringBootTest
public class ConfigPropertiesCheckerIntegrationTest {

    @Autowired
    String secondProperty;

    @Test
    void checkAutoConfigEndpointProperties() {
        assertThat(secondProperty, is(notNullValue()));
    }
}

So question: how to ignore first.property and say Spring just skip it?

Answer 1

You can disable {cipher} ed properties decryption with spring.cloud.decrypt-environment-post-processor.enabled=false . Eg:

@SpringBootTest(properties = "spring.cloud.decrypt-environment-post-processor.enabled=false")