[英]mongoose, graphQL query returning null data though exist in mongo
I am trying to use a query in NodeJS using mongoose + GraphQL.我正在尝试使用 mongoose + GraphQL 在 NodeJS 中使用查询。
The model file as: model 文件为:
const mongoose = require('mongoose')
mongoose.set('debug', true);
const Schema = mongoose.Schema
const authorSchema = new Schema({
name: String,
age: Number,
authorId: String,
})
module.exports = mongoose.model('Author', authorSchema)
Schema for author is as below:作者的架构如下:
const AuthorType = new GraphQLObjectType({
name: 'Author',
fields: () => ({
authorId: {type: GraphQLString},
name: {type: GraphQLString},
age: {type: GraphQLInt},
books: {
type: new GraphQLList(BookType),
resolve(parent, args) {
return book.find({authorId: parent.authorId})
}
},
})
})
The rootQuery:根查询:
const RootQuery = new GraphQLObjectType({
name: 'RootQueryType',
fields: {
author: {
type: AuthorType,
args: {authorId: {type: GraphQLString}},
resolve(parent, args){
console.log("Author parent", parent, args)
return Author.find({authorId: args.authorId})
}
},
Now when I am trying to use query from graphiQL using authorId, it returns as null, I have enabled mongoose debug, I see that mongoose sending correct query.现在,当我尝试使用 authorId 从 graphiQL 使用查询时,它返回为 null,我启用了 mongoose 调试,我看到 mongoose 发送了正确的查询。
{
author(authorId: "1") {
name
age
authorId
}
}
It returns below它在下面返回
{
"data": {
"author": {
"name": null, <<<<
"age": null, <<<
"authorId": null <<<
}
}
}
But I see that in mongoose log, it sends correctly但我看到在 mongoose 日志中,它发送正确
Mongoose: authors.find({ authorId: '1' }, { projection: {} })
In my mongo db, I have the data for authorId as below:在我的 mongo 数据库中,我有 authorId 的数据如下:
Atlas atlas-5p0amv-shard-0 [primary] test> db.authors.find({authorId: '1'})
[
{
_id: ObjectId("63adf57d50ee6abd7cce79ad"),
name: 'Author1',
age: 44,
authorId: '1',
__v: 0
}
]
Atlas atlas-5p0amv-shard-0 [primary] test>
Can you please let me know where I am doing wrong.你能告诉我我哪里做错了吗?
Thanks in advance.提前致谢。
With Regards, -M-此致,-M-
As per the comment above, you want Author.findOne
not Author.find
since you'd want a single document, not an array.根据上面的评论,您需要Author.findOne
而不是Author.find
,因为您需要一个文档,而不是一个数组。
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