Luxon：根据地区设置按工作日开始对所有工作日进行排序

Question

Is there a easy way to get all week day names sorted depending on locale?

Info.weekdays() seems to be pretty close to what I want, but the sorting is not how I would expect it.

Example:

const info = luxon.Info

console.log(info.weekdays('short', {locale: 'de'}));
// actual: ['Mo', 'Di', 'Mi', 'Do', 'Fr', 'Sa', 'So']

console.log(info.weekdays('short', {locale: 'en-US'}));
// actual: ['Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun']
// expected: ['Sun', 'Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat']

Is there maybe a util function to get the start of week for a locale to resort this array or is there a more easy approach with the Intl API?

Thanks in advance!

Answer 1

Based on tickets in luxon's repo #373 and #939 which are about similar cases and up to discussion - everything was blocked by browser API was not providing such information.

Nowadays, TC39 proposal has already been shipped( source: MDN ) to Chrome 99+, Safari 15.4+, Edge. Unfortunately, not to Firefox. Yet.

Looks like luxon's team did not revisited this feature so far, I don't see any reference to weekInfo in their code, conditional or not. So you probably better to implement your homebrew algo:

(new Intl.Locale('en-GB')).weekInfo.firstDay // 1
(new Intl.Locale('en-US')).weekInfo.firstDay // 7

and if weekInfo will not be available to FF, with fallback to either Sunday or Monday.