我不得不使用 filter() 方法重构 function，但我失败了

Question

The original code of the function was:

getGreaterThan: function(input) {
  let greaterValues = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
  let greaterNums = [];
  for (let j = 0; j < greaterValues.length; j++) {
    if (greaterValues[j] > parseInt(input)) {
      greaterNums.push(greaterValues[j]);
    }
  }
  return greaterNums;
}

This is my implementation:

return [parseInt(input).filter((greaterNum) => input < greaterNum)];]

How can I proceed with this?

Answer 1

You should be filtering greaterValues , not parseInt(input) .

There's no need to put [] around the return value. filter() returns an array by itself.

getGreaterThan: function(input) {
  const greaterValues = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
  input = parseInt(input); // no need to do this each time through the loop
  return greaterValues.filter(val => val > input);
}