[英]How to find the first column with a certain value for each row with dplyr
I have a dataset like this:我有一个这样的数据集:
df <- data.frame(id=c(1:4), time_1=c(1, 0.9, 0.2, 0), time_2=c(0.1, 0.4, 0, 0.9), time_3=c(0,0.5,0.3,1.0))
id time_1 time_2 time_3
1 1.0 0.1 0
2 0.9 0.4 0.5
3 0.2 0 0.3
4 0 0.9 1.0
And I want to identify for each row, the first column containing a 0, and extract the corresponding number (as the last element of colname), obtaining this:我想识别每一行,第一列包含一个 0,并提取相应的数字(作为 colname 的最后一个元素),获得:
id time_1 time_2 time_3 count
1 1.0 0.1 0 3
2 0.9 0.4 0.5 NA
3 0.2 0 0.3 2
4 0 0.9 1.0 1
Do you have a tidyverse
solution?你有
tidyverse
解决方案吗?
We may use max.col
我们可以使用
max.col
v1 <- max.col(df[-1] ==0, "first")
v1[rowSums(df[-1] == 0) == 0] <- NA
df$count <- v1
-output -输出
> df
id time_1 time_2 time_3 count
1 1 1.0 0.1 0.0 3
2 2 0.9 0.4 0.5 NA
3 3 0.2 0.0 0.3 2
4 4 0.0 0.9 1.0 1
Or using dplyr
- use if_any
to check if there are any 0 in the 'time' columns for each row, if there are any, then return the index of the 'first' 0 value with max.col
( pick
is from devel version, can replace with across
) within the case_when
或使用
dplyr
- 使用if_any
检查每一行的“时间”列中是否有任何 0,如果有,则返回带有max.col
的“第一个”0 值的索引( pick
来自 devel 版本,可以在case_when
中替换为across
)
library(dplyr)
df %>%
mutate(count = case_when(if_any(starts_with("time"), ~ .x== 0) ~
max.col(pick(starts_with("time")) ==0, "first")))
-output -输出
id time_1 time_2 time_3 count
1 1 1.0 0.1 0.0 3
2 2 0.9 0.4 0.5 NA
3 3 0.2 0.0 0.3 2
4 4 0.0 0.9 1.0 1
You can do this:你可以这样做:
df <- df %>%
rowwise() %>%
mutate (count = which(c_across(starts_with("time")) == 0)[1])
df
id time_1 time_2 time_3 count
<int> <dbl> <dbl> <dbl> <dbl>
1 1 1 0.1 0 3
2 2 0.9 0.4 0.5 NA
3 3 0.2 0 0.3 2
4 4 0 0.9 1 1
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.