如何使用 nextcord python 在回调 function 中调用 function

Question

@bot.slash_command(guild_ids=[1061756784567656448])
async def oui(ctx):
    button = Button(label="A + 1", style=ButtonStyle.blurple)
    myview = View(timeout=180)
    myview.add_item(button)
    
    
    async def aurevoir(ctx):
        await ctx.send_message("aurevoir")
        
    
    async def bonjour(interaction: discord.Interaction):
        await interaction.response.send_message("bonjour")
        await aurevoir(ctx)
        
    button = Button(label="A + 1", style=ButtonStyle.blurple)
    myview = View(timeout=180)
    myview.add_item(button)
        
    
    button.callback = bonjour
    await ctx.send(f"hello",view= myview)

The function "aurevoir" never sends the message, and I got a lot of errors like 'Context' object has no attribute 'send_message'. I don't know how to fix it.

Answer 1

The issue is that you were passing the ctx object through - it'd be better to use the interaction object that bonjour gets when you press the button and using the followup property on the interaction to send the message.

async def oui(ctx: discord.ApplicationContext):
    await ctx.defer()
    button = Button(label="A + 1", style=ButtonStyle.blurple)
    myview = View(timeout=180)
    myview.add_item(button)
    
    async def aurevoir(interaction: discord.Interaction):
        await interaction.followup.send("aurevoir")
        
    async def bonjour(interaction: discord.Interaction):
        await interaction.response.send_message("bonjour")
        await aurevoir(interaction)
        
    button = Button(label="A + 1", style=ButtonStyle.blurple)
    myview = View(timeout=180)
    myview.add_item(button)
        
    button.callback = bonjour
    await ctx.followup.send("hello", view=myview)

I also added a ctx.defer and a ctx.followup.send .