[英]How do I overload a function with named parameters in TypeScript?
I have a function which I want to be able to pass normal arguments and keyword (named) arguments. Yet, whenever I try doing the overload I get an error.我有一个 function,我希望能够传递正常的 arguments 和关键字(命名)arguments。但是,每当我尝试进行重载时,我都会收到错误消息。
I tried overloading the function this way:我尝试以这种方式重载 function:
function myFunc({name, surname, age}: myFuncParams): string;
function myFunc(name: string, surname?: string, age?: number): string;
function myFunc(nameOrObj: string | myFuncParams, surname?: string, age?: number): string {
// do something and return a string
return ""
};
Where:在哪里:
interface myFuncParams {
name: string,
surname?: string,
age?: number
}
Of course this is a simplification of a bit more complicated case;当然,这是对更复杂的情况的简化; but the idea here is to be able to pass name and age, for example;
但是这里的想法是能够传递姓名和年龄,例如; without having to move surname or doing the following:
无需移动姓氏或执行以下操作:
myFunc("Foo", null, 111);
And just doing:只是在做:
myFunc({name:"Foo", age:111});
I get the following error:我收到以下错误:
function myFunc({name, surname?, age?}: myFuncParams): string;
// ^: This overload signature is not compatible with its implementation signature. (2394)
function myFunc(name: string, surname?: string, age?: number): string;
function myFunc(nameOrObj: string | myFuncParams, surname?: string, age?: number): string {
// do something and return a string
return ""
};
Typescript playground link : Typescript 游乐场链接:
Edit: as @jonrsharpe's pointed:编辑:正如@jonrsharpe 指出的那样:
function myFunc({name, surname, age}: myFuncParams): string;
function myFunc(name: string, surname?: string, age?: number): string;
function myFunc(nameOrObj: string | myFuncParams,surname?: string,age?: number): string {
return ""
};
Forgot to mark surname and age as optional in the final declaration.忘记在最终声明中将姓氏和年龄标记为可选。
Try this way试试这个方法
function myFunc(opts: myFuncParams): string;
function myFunc(name: string, surname?: string, age?: number): string;
function myFunc(nameOrObj: string | myFuncParams, surname?: string, age?: number): string {
// do something and return a string
return ""
};
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