单击 ionic 5 中的硬件后退按钮退出应用程序的逻辑中的编译错误

Question

I have created an App with following Details - Ionic version - 5.4.16 Cordova version - 11.0.0 Angular CLI - 14.2.3 typescript - 4.8.3 npm - 8.15.0 node - 16.17.0

I want to exit an App on click of hardware back button. I have written below logic to exit the App - navigator["app"].exitApp();

But this logic is giving me compilation error -

var navigator: Navigator Element implicitly has an 'any' type because expression of type '"app"' can't be used to index type 'Navigator'. Property 'app' does not exist on type 'Navigator'.

This is the compilation error image

Please help me with the solution to this error or any other way to exit an App using hardware back button in ionic 5 and cordova.

Thanks

Answer 1

  navigator.app.exitApp();

in our code we do it with this line, so I think you might have the wrong syntax. I believe app is a property of navigator, you can check with a debugger. Also, are you using typeScript? That seems like a typescript error.