[英]How can i pass this complex Json MAP Data into flutter Listview
i am new to flutter, and i meet this API with complex "MAP" json. What i want is to display the list of countries with their details in flutter listview, How can i achieve that?我是 flutter 的新手,我遇到了这个 API 和复杂的“MAP”json。我想要的是在 flutter listview 中显示国家列表及其详细信息,我该如何实现? Most of answers explain about "LIST" json.
大多数答案都解释了“LIST”json。
{
"status": "Request is successful",
"message": null,
"data": {
"page": 1,
"last_page": 125,
"page_size": 2,
"countries": [
{
"id": "1",
"attributes": {
"name": "Grenada",
"code": "GD",
"subregion": "Caribbean",
"flag": "https://flagcdn.com/gd.svg",
"postalcode": "",
"latitude": "12.11666666",
"longitude": "-61.66666666",
"createdAt": "2023-01-11T22:15:40.000000Z",
"updatedAt": "2023-01-11T22:15:40.000000Z"
}
},
{
"id": "2",
"attributes": {
"name": "Malaysia",
"code": "MY",
"subregion": "South-Eastern Asia",
"flag": "https://flagcdn.com/my.svg",
"postalcode": "^(\\d{5})$",
"latitude": "2.5",
"longitude": "112.5",
"createdAt": "2023-01-11T22:15:40.000000Z",
"updatedAt": "2023-01-11T22:15:40.000000Z"
}
}
]
}
}
I found this GitHub project with these files json , modelClass Mainclass which relate with the concept but mine is has got one extra braces (map) so i do not know how to achieve the goal.我发现这个GitHub 项目包含这些文件json ,与概念相关的modelClass Mainclass但我的有一个额外的大括号(地图)所以我不知道如何实现目标。
if there any suggestion or best way to code please help me.如果有任何建议或最佳编码方式,请帮助我。
this is how they created in model class but, but it does not work with me.这就是他们在 model class 中创建的方式,但是对我不起作用。
class Product {
final List<Result> results;
Product({this.results});
factory Product.fromJson(Map<String, dynamic> data) {
var list = data['data']['result'] as List;
List<Result> resultList = list.map((e) => Result.fromJson(e)).toList();
return Product(
results: resultList,
);
}
}
what i have done is我所做的是
class MyStatefulWidget extends StatefulWidget {
const MyStatefulWidget({super.key});
@override
State<MyStatefulWidget> createState() => _MyStatefulWidgetState();
}
class _MyStatefulWidgetState extends State<MyStatefulWidget> {
var data_from_link;
getData() async {
final String link = 'myurl';
data_from_link = await http.get(Uri.parse(link), headers: {"Accept": "application/json"});
final res = jsonDecode(data_from_link.body) as Map<String, dynamic>;
final List<Country> list= (res['data']['countries'] as List<dynamic>).map((e) => Country.fromJson(e))
.toList();
}
@override
void initState() {
super.initState();
getData();
}
@override
Widget build(BuildContext context) {
final res = jsonDecode(data_from_link.body) as Map<String, dynamic>;
final List<Country> list= (res['data']['countries'] as List<dynamic>).map((e) => Country.fromJson(e))
.toList();
return ListView.builder(
itemCount: list.length,
itemBuilder: (_, i) => ListTile(
title: Text(
list![i].attributes.name,
),
subtitle: Text(list![i].attributes.code),
)
);
}
}
You can create two classes for Country
and Attribute
您可以为
Country
和Attribute
创建两个类
class Country {
const Country({required this.id, required this.attributes});
/// Creates a Country from Json map
factory Country.fromJson(Map<String, dynamic> json) => Country(
id: json['id'] as String,
attribute:
Attribute.fromJson(json['attributes'] as Map<String, dynamic>),
);
/// A description for id
final String id;
final Attribute attributes;
}
class Attribute {
const Attribute({
required this.name,
required this.code,
required this.createdAt,
required this.updatedAt,
});
/// Creates a Attribute from Json map
factory Attribute.fromJson(Map<String, dynamic> json) => Attribute(
name: json['name'] as String,
code: json['code'] as String,
createdAt: DateTime.parse(json['createdAt'] as String),
updatedAt: DateTime.parse(json['updatedAt'] as String),
);
final String name;
final String code;
final DateTime createdAt;
final DateTime updatedAt;
}
when decoding:解码时:
final res = jsonDecode(json) as Map<String, dynamic>;
final List<Country> list = (res['data']['countries'] as
List<dynamic>)
.map((e) => Country.fromJson(e))
.toList();
Thank you but how can i print or call data from country attribute after decoding because when i try something like Print (list.country.attribute.name).
谢谢,但是我如何在解码后打印或调用国家属性的数据,因为当我尝试打印(list.country.attribute.name)之类的东西时。 I fail.
我失败了。 My goal is to display on Listview
我的目标是在 Listview 上显示
You can use it like this:你可以像这样使用它:
ListView.builder(
itemCount: list.length,
itemBuilder: (_, i) => ListTile(
title: Text(
list[i].attributes.name,
),
subtitle: Text(list[i].attributes.code),
)),
UPDATE
更新
import 'package:flutter/material.dart';
class MyStatefulWidget extends StatefulWidget {
const MyStatefulWidget({super.key});
@override
State<MyStatefulWidget> createState() => _MyStatefulWidgetState();
}
class _MyStatefulWidgetState extends State<MyStatefulWidget> {
late Future<List<Country>> futureList;
Future<List<Country>?> getData() async {
final String link = 'yoururl';
final res = await http
.get(Uri.parse(link), headers: {"Accept": "application/json"});
if (response.statusCode == 200) {
final List<Country> list = (res['data']['countries'] as List<dynamic>)
.map((e) => Country.fromJson(e))
.toList();
return list;
} else {
throw Exception('Failed to fetch data');
}
}
@override
void initState() {
super.initState();
futureList = getData();
}
@override
Widget build(BuildContext context) {
return FutureBuilder(
future: futureList,
builder: (context, snapshot) {
if (snapshot.hasData) {
final list = snapshot.data;
return ListView.builder(
itemCount: list!.length,
itemBuilder: (_, i) => ListTile(
title: Text(
list![i].attributes.name,
),
subtitle: Text(list![i].attributes.code),
),
);
} else if (snapshot.hasError) {
return const Text('error fetching data');
}
return const CircularProgressIndicator();
},
);
}
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.