Swift 通过搜索词数组过滤数组结构

Question

I have created an array struct to house my values used in a list. Now I want to be able to search this list and every time the user makes a blank space it should be viewed by the program as two different searchwords that should both be met. I have successfully created a function to get the searchwords but I don't really get how to now filter my stuctArray by all the searchWords.

let searchWords = findAllSearchResutsRecursive(searchWord) //example ["A", "B", ,"C"]

let filteredArray = listArray.filter {
    for word in searchWords {
        $0.firstname!.capitalized.contains(word.capitalized) ||
        $0.lastname!.capitalized.contains(word.capitalized) ||
        $0.id!.capitalized.contains(word.capitalized) ||
        $0.city!.capitalized.contains(word.capitalized)
    }
}

To clarify, if the searchWords is ["A", "N"] and one of the participants (people in the list) has the firstname "Anna" but nothing else match the search I still want to show it.

Alternatively is if it would be better to convert the SearchWords to a set and in that way somehow filter them all at the same time.

This is errors I get:

Answer 1

You could rewrite it like this:

let searchWords = findAllSearchResutsRecursive(searchWord) //example ["A", "B", ,"C"]

let filteredArray = listArray.filter {
    var matchFound = false
    for word in searchWords {
        if (
          $0.firstname!.capitalized.contains(word.capitalized) ||
          $0.lastname!.capitalized.contains(word.capitalized) ||
          $0.id!.capitalized.contains(word.capitalized) ||
          $0.city!.capitalized.contains(word.capitalized)
        ) {
            matchFound = true
          }
    }
    return matchFound
}

Answer 2

The outer filter function needs to return a boolean value. To not iterate over all remaining words if a match is found you could use:

let filteredArray = listArray.filter {
    var result = false
    for word in searchWords {
        
        // check if any property contains the word
        if $0.firstname!.capitalized.contains(word.capitalized) ||
        $0.lastname!.capitalized.contains(word.capitalized) ||
        $0.id!.capitalized.contains(word.capitalized) ||
            $0.city!.capitalized.contains(word.capitalized){
            // set the result and break the loop
            result = true
            break
        }
    }
    // return the result
    return result
}