用于删除特殊字符的正则表达式

Question

I need a kotlin function that will remove specific special characters from a string.

The list of the special chars: []'()*"'
Data also contains €˜€™ Ÿ'Ÿ

private val specialCharRemoval = "[‘()*’\\\"|\u0099|\u009C|']".toRegex()


fun deaccent(keyword: String): String {
    keyword.replace(specialCharRemoval, "")
}

I tested

String tokens = "\"book*‘\"  ¼ ¶childΩ 7 â\u0080\u0098play* for| the  â " +
                "future\u0080\u0099 sizeð\u009F\u0091\u009F11.5 (men's)"

String expected = "book  ¼ ¶childΩ 7 play for the â future sizeð 11.5 mens"

But got:

String actual = ""book*‘"  ¼ ¶childΩ 7 ‘play* for| the  â future€™ size👟11.5 (men’s)"

What is wrong?

Answer 1

It is necessary to escape special characters [ ] ( ) * |

And surround all the characters you are looking for with square brackets [ ]

val str = "\"book*‘\"  ¼ ¶childΩ 7 â\u0080\u0098play* for| the  â future\u0080\u0099 sizeð\u009F\u0091\u009F11.5 (men's)"
val regex = "[\\[\\]‘\\(\\)\\*\"'\\|\u0080\u0098\u0080\u0099\u009F\u0091\u009F]".toRegex()

println(str.replace(regex, ""))