Python 关闭 windows 中所有打开的应用程序的代码

Question

I am working on pyautogui for locateonscreen but I need to make sure I have a clean windows prior to running it.

I need help with a code that will kill/close all open/active windows application and then open a single exe using subprocess.

Answer 1

you can use the psutil library to close all open/active windows applications and then open a single exe using the subprocess module:

import psutil
import subprocess

# Kill all open/active processes
for proc in psutil.process_iter():
    proc.kill()

# Open a single exe using subprocess
subprocess.Popen("C:\\path\\to\\exe.exe")

Note that the psutil.process_iter() returns a list of all running processes on the system, and proc.kill() method is used to kill each process. The subprocess.Popen method is used to open the exe file. Make sure that you provide the correct path to the exe file. Please be aware that this script will close all open applications, including any unsaved work in progress. You should use it with caution, or for testing purpose only.

you can instead reduce all open windows. this is safer!

import win32gui
import win32con
import subprocess

def minimize_all():
    def callback(hwnd, hwnds):
        if win32gui.IsWindowVisible(hwnd) and win32gui.IsWindowEnabled(hwnd):
            hwnds.append(hwnd)
        return True

    hwnds = []
    win32gui.EnumWindows(callback, hwnds)
    for h in hwnds:
        win32gui.ShowWindow(h, win32con.SW_MINIMIZE)

minimize_all()
# Open a single exe using subprocess
subprocess.Popen("C:\\path\\to\\exe.exe")

This script uses the win32gui library to enumerate all open windows, and the win32con library to minimize them.

Answer 2

why not minimize all windows with shortcut WIN + D ?

import pyautogui
pyautogui.hotkey('winleft','d')