[英]How to open popup in JavaScript? (NOT window.open)
This is kind of a dumb question, but what is the command to open a popup window in JS?这是一个愚蠢的问题,但是在 JS 中打开弹出窗口 window 的命令是什么? I know that window.open works, but on chrome, it shows the tabs, which I have seen in popups not existing.
我知道 window.open 有效,但在 chrome 上,它显示了我在不存在的弹出窗口中看到的选项卡。 It should just show the address at the top.
它应该只在顶部显示地址。 Hopefully I expressed this question correctly.
希望我正确表达了这个问题。
Default behavior is to open in a new tab.默认行为是在新选项卡中打开。 However, using the third parameter
windowFeatures
in the window.open(...);
但是,在
window.open(...);
中使用了第三个参数windowFeatures
; function will allow you to set parameters to force the request to open in a new popup with the minimal UI elements that you're requesting. function 将允许您设置参数以强制请求在新的弹出窗口中打开,其中包含您请求的最少 UI 元素。 For example:
例如:
window.open("{url}", "_blank", "popup=yes");
Reference Documentation: window.open()
参考文档:
window.open()
Specifying the popup
option in the windowsFeatures
(third) parameter should produce the result you want.在
windowsFeatures
(第三个)参数中指定popup
选项应该会产生您想要的结果。
window.open('', '', 'popup=true')
Learn more about window.open
from MDN, here.在此处从 MDN 了解有关
window.open
的更多信息。
Hope this helps.希望这可以帮助。
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