带有字段和变量的简单模式匹配在 GAWK/AWK 中似乎不起作用

Question

I am trying to extract all lines where a field matches a pattern which is defined as a variable. I tried the following

head input.dat |
awk -F '|' -v CODE="39905|19043" '{print $13; if($13~CODE){print "Matched"} else {print "Nomatch"} }'

I am printing the value of the field before attempting a pattern match.(This way I don't have to show the entire line that contains many fields) This is the output I got.

PLAN_ID
Nomatch
39905
Nomatch
39905
Nomatch
39883
Nomatch
19043
Nomatch
2215
Nomatch
19043
Nomatch
9149
Nomatch
42718
Nomatch
24
Nomatch

I expected to see at least 3 instances of Matched in the output. What am I doing wrong?

---

_{edit by @Fravadona}

xxd input.dat | head -n 6

00000000: fffe 4d00 4f00 4e00 5400 4800 5f00 4900 ..M.O.N.T.H._.I.
00000010: 4400 7c00 5300 5600 4300 5f00 4400 5400 D.|.S.V.C._.D.T.
00000020: 7c00 5000 4100 5400 4900 4500 4e00 5400 |.P.A.T.I.E.N.T.
00000030: 5f00 4900 4400 7c00 5000 4100 5400 5f00 .I.D.|.P.A.T..
00000040: 5a00 4900 5000 3300 7c00 4300 4c00 4100 Z.I.P.3.|.C.L.A.
00000050: 4900 4d00 5f00 4900 4400 7c00 5300 5600 I.M._.I.D.|.S.V.

Turns out that the input file uses the UTF-16 LE Encoding (as shown by the hexdump of the content). Thus, the solution seems to be to convert the input file from UTF-16LE to UTF-8 before running AWK. Thanks

Answer 1

I found out (thanks to all who suggested looking at the hexdump of the input file) that the file used UTF-16LE encoding. Once I converted the input file using iconv , the AWK script worked as expected