[英]keep input name in ffmpeg?
can someone help me to keep original name in input as output有人可以帮助我将原始名称保留为 output
For example, i have a "Video.mp4" i need to convert it in mp3 as "Video.mp3"例如,我有一个“Video.mp4”,我需要在 mp3 中将其转换为“Video.mp3”
but i cant find it how to do it!但我找不到怎么做!
i try ffmpeg -i video.mp4 -b:a 192K -vn music.mp3
我试试
ffmpeg -i video.mp4 -b:a 192K -vn music.mp3
but the output file is "music.mp3" and i dont want it但是 output 文件是“music.mp3”,我不想要它
soo i try ffmpeg -i A.mp4 -b:a 192K -vn *.mp3
所以我试试
ffmpeg -i A.mp4 -b:a 192K -vn *.mp3
and it gives error like:它给出了如下错误:
*.mp3: Invalid argument
pls help me:(请帮助我:(
[untried] [未尝试]
@echo off
ffmpeg -i "%~1" -b:a 192K -vn "%~n1.mp3"
As a batch file named tomp3.bat
, use as tomp3 "video.mp4"
作为名为
tomp3.bat
的批处理文件,用作tomp3 "video.mp4"
The quotes are not required unless the filename contains spaces (or some other symbols)除非文件名包含空格(或其他一些符号),否则不需要引号
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