如果一行有特定条目，则在 output 中创建一个空行

Question

I have input.txt like so:

237 @
0 2 3 4 0. ABC
ABC
DEF
@ 237
0 1 4 7 2 0.
0 3 8 9 1 0. GHI
XYZ

(a) If a row contains the symbol @ , then, in the output, I want a newline/blankline.

(b) If a row starts with a 0 and contains 0. then, the interval of such entries excepting the terminating 0. should be displayed.

The following script accomplishes (b)

awk '{
    for (i=1; i<NF; i++)
        if($i == "0")
            {arr[NR] = $i}
        else
            if ($i == "0.") 
                {break}
            else 
                {arr[NR]=arr[NR]" "$(i)}}
    ($1 == "0") {print arr[NR]}
    ' input.txt > output.txt

so that the output is:

0 2 3 4
0 1 4 7 2
0 3 8 9 1

How can (a) be accomplished so that the output is:

                // <----Starting newline
0 2 3 4

0 1 4 7 2
0 3 8 9 1

Answer 1

try add if ($0 ~ /@/) {print ""}

so

awk '{
    for (i=1; i<NF; i++)
        if($i == "0")
            {arr[NR] = $i}
        else
            if ($i == "0.") 
                {break}
            else 
                {arr[NR]=arr[NR]" "$(i)}
    if ($0 ~ /@/) {print ""} 
    ($1 == "0") {print arr[NR]}
    ' soinput.txt > output.txt

Answer 2

Is this what you're trying to do?

$ awk '/@/{print ""} /^0/ && sub(/ 0\..*/,"")' file

0 2 3 4

0 1 4 7 2
0 3 8 9 1