是否可以使用“for loop grep”命令？

Question

I have lots of files in every year directory

and in each file have long and large sentence like this for exmaple

• List item

home/2001/2001ab.txt

the AAAS kill every one not but me and you and etc
the A1CF maybe color of full fill zombie

home/2002/2002ab.txt

we maybe know some how what

home/2003/2003ab.txt

Mr, Miss boston, whatever
aaas will will will long long

and in home directory, I got home/reference.txt (list of word file)

A1BG
A1CF
A2M
AAAS

I'd like to do count how many word in the file reference.txt is in every single year file

this is my code where I run in every year directory home/2001/ , home/2002/ , home/2003/

# awk
function search () {
    awk -v pattern="$1" '$0 ~ pattern {print}'  *.txt > $1
}

# load custom.txt
for i in $(cat reference.txt)
do 
 search $i 
done

# word count
wc -l * > line-count.txt 

this is my result

home/2001/A1BG

$cat A1BG
0

home/2001/A1CF

$cat A1CF
1

home/2001/A2M

$cat A2M
0

home/2001/AAAS

$cat AAAS
1

home/2001/line-count.txt

$cat line-count.txt
2021ab.txt 2
A1BG 
A1CF 1
A2M 0
AAAS 1

result line-count.txt file have all information what I want but I have to do this work repeat manually do cd directory do run my code and then cd directory I have around 500 directory and file, it is not easy

and second problem is wasty bunch of file create lots of file and takes too much time

because of this at first I'd likt use grep command but I dont' know how to use list of file instead of single word

that is why I use awk

How can i do it more simple

Answer 1

at first I'd likt use grep command but I dont' know how to use list of file instead of single word

You might use --file=FILE option for that purpose, selected file should hold one pattern per line.

How can i do it more simple

You might use --count option to avoid need of using wc -l for that, consider following simple example, let file.txt content be

123
456
789

and file1.txt content be

abc123
def456

and file2.txt content be

ghi789
xyz000

and file3.txt content be

xyz000
xyz000

then

grep --count --file=file.txt file1.txt file2.txt file3.txt

gives output

file1.txt:2
file2.txt:1
file3.txt:0

Observe that no files are created and file without matches does appear in output. Disclaimer : this solution assumes file.txt does not contain character of special meaning for GNU grep , if this does not hold do not use this solution.

(tested in GNU grep 3.4)