[英]Most concise way to check whether a list is empty or contains only None?
Most concise way to check whether a list is empty or contains only None? 最简洁的方法来检查列表是空的还是只包含None?
I understand that I can test: 我明白我可以测试:
if MyList:
pass
and: 和:
if not MyList:
pass
but what if the list has an item (or multiple items), but those item/s are None: 但是如果列表有一个项目(或多个项目),但那些项目是无:
MyList = [None, None, None]
if ???:
pass
One way is to use all
and a list comprehension: 一种方法是使用
all
和list comprehension:
if all(e is None for e in myList):
print('all empty or None')
This works for empty lists as well. 这也适用于空列表。 More generally, to test whether the list only contains things that evaluate to
False
, you can use any
: 更一般地,要测试列表是否仅包含评估为
False
,您可以使用any
:
if not any(myList):
print('all empty or evaluating to False')
You can use the all()
function to test is all elements are None: 你可以使用
all()
函数来测试所有元素都是None:
a = []
b = [None, None, None]
all(e is None for e in a) # True
all(e is None for e in b) # True
You can directly compare lists with ==
: 您可以直接将列表与
==
进行比较:
if x == [None,None,None]:
if x == [1,2,3]
If you are concerned with elements in the list which evaluate as true: 如果您关注列表中评估为true的元素:
if mylist and filter(None, mylist):
print "List is not empty and contains some true values"
else:
print "Either list is empty, or it contains no true values"
If you want to strictly check for None
, use filter(lambda x: x is not None, mylist)
instead of filter(None, mylist)
in the if
statement above. 如果要严格检查
None
,请在上面的if
语句中使用filter(lambda x: x is not None, mylist)
而不是filter(None, mylist)
。
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