在c＃“ C：\\\\ WINDOWS \\\\ system32 \\\\ vsjitdebugger.exe -p％ld -e％ld -g％ld \\”中的此命令是什么

Question

i came across this command, i want to know what this command for, and what are the options for? i am looking for brief introduction & any source links for basic explanation.

Thanks,

Answer 1

This is not a C# command is just a windows program. Specifically is the Visual Studio Just In time Debugger. The -p %ld -e %ld -g %ld are arguments that are passed to this program.

Run vsjitdebugger.exe /? to understand what this arguments are. Google the program name(sdjitdebugger.exe) if you need more info.

Answer 2

VSJITDEBUGGER is the Visual Studio Just-in-time debugger. The command you're seeing in your source code is attempting to run it with some specific arguments:

vsjitdebugger
    -p <processId>
    -e <??>
    -g <??>

I don't know what the -e and -g arguments are for, I've never used them. The -p specifies a process ID to attach the debugger to.

The "%ld" sections of the string are printf-formatting so you can insert the process ID (and other arguments) before running the command.