PHP的日期格式为mm-dd-yyyy

Question

I have a date in the following format

MM-DD-YYYY

How can I convert this to UNIX time in PHP

Thanks

Having a small problem

$date = strtotime($_POST['retDate']);
print $date; //Prints nothing
print $_POST['retDate']; //Prints 08-18-2009

Answer 1

If the format is always like that, I'd would try something like:

list($m,$d,$y) = explode('-', '08-18-2009');
$time = mktime(0, 0, 0, $m, $d, $y);
print date('m-d-Y', $time);

As for your example, the problem is the function fails. You should check it like so:

if(($time=strtotime('08-18-2009'))!==false)
{
 // valid time format
}
else
 echo 'You entered an invalid time format';

Answer 2

or you can use php date obyek to do that, like this

$tgl = "30-12-2013";
$tgl2 = DateTime::createFromFormat('d-m-Y', $tgl);
print_r($tgl2);
echo($tgl2->format('Y-m-d'));

i hope this can help...

Answer 3

Use strtotime :

$str = "03-31-2009";
$unixtime = strtotime($str);

Answer 4

Since these answers and comments were provided, PHP has updated to include a native function that suits this situation perfectly. Check out PHP's DateTime object here . This includes a createFromFormat method that will do as requested. In this particular example:

$date = DateTime::createFromFormat('j-M-Y', $_POST['retDate']);

From there, you can format it as desired or perform any other date operations:

echo $date->format('Y-m-d');

And that's it! Keep in mind that this is only provided in PHP 5.3.0 or higher!