PHP无法从MySQL数据库回显ID字段

Question

I'm trying to print an ID from MySQL, the field loads into an array and is visible via print_r but I can't echo it or transfer it to another variable ... what am I missing?

if ( $_POST['section'] == "freelance" ) {
    $field_name = "promoter";
} else {
    $field_name = "connector";
}
echo $row[$field_name.'_login_ID']

As requested the results of var_dump($row)

array(13) {
   ["connector_login_id"] =>  string(2) "14"
   ["connector_type"] =>  string(10) "non-profit"
   ["unique_code"] =>  string(9) "test-t001"
   ["update_code"] =>  string(1) "N"
   ["md5ID"] =>  string(0) ""
   ["username"] =>  string(6) "bugger"
   ["connectorEmail"] =>  string(17) "gzigner@gmail.com"
   ["password"] =>  string(32) "098f6bcd4621d373cade4e832627b4f6"
   ["connectorPass"] =>  string(4) "test"
   ["active"] =>  string(1) "Y"
   ["modified"] =>  string(19) "2009-08-21 15:37:22"
   ["lastlogin"] =>  string(19) "0000-00-00 00:00:00"
   ["md5email" ]=>  string(32) "051cba58da33fac6b2d18af5182079f4"
} 

Answer 1

$row[$field_name.'_login_ID']   <-- "ID"

array(13) {
    ["connector_login_id"]      <-- "id"

Seems like a simple typo to me.

Alternatively, are you sure $field_name gets set to 'connector' , since 'promoter_login_id' doesn't exist in this array.

Answer 2

This is purely speculation without your code, but it's probable that the field you are trying to echo contains a hyphen, eg "mytable-id", considering that it does indeed show when you use print_r() to print out the entire array. If this is the case you would need to use {'mytable-id'} to get/echo it's value:

echo($dataArray->MyTable->{'mytable-id'});

*Edit : I don't know if your code is copy and pasted, but the value you are trying to print is:

echo $row[$field_name.'_login_ID'];

instead of:

echo $row[$field_name.'_login_id'];

PHP is case-sensitive. You could also try this:

$field_name = $field_name.'_login_id';
echo $row[$field_name];

or

$field_name = $field_name.'_login_id';
echo $row['$field_name'];